If C ( the velocity of light ) g , ( the acceleration due to gravity), P ( the atmospheric pressure) are the fundamental quantities in MKS system , then the dimensions of length will be same as that of

If the velocity of light denoted by 'c', acceleration due to gravity 'g' and atmospheric pressure 'p' are taken as fundamental units, then the dimensional formula of length will be :

If force, acceleration and time are taken as fundamental quantities, then the dimensions of length will be:

If the speed of light c, acceleration due to gravity (g) and pressure (p) are taken as the fundamental quantities then the dimension of gravitational constant is

If velocity of light, acceleration due to gravity and normal atmospheric pressure are taken as the fundamental units, what will be the units of mass, length and time? Given velocity of light 3 xx 10^(8) ms^(-1) , accelerating due to gravity 10ms^(-2) and normal pressure = 10^(5) Nm^(-2) .

If in a system force (F), pressure (P) and time(T) is fundamental unit, then dimensional formulae for length will be:

If Pressure, mass and velocity are fundamental physical quantities, the dimension of force (F) will be

If velocity of light c, planck's constant h and gravitational constnat G are taken as fundamental quantities then the dimensions of the length will be