The resistance R=(V)/(I), whereV=100pm5V...

The resistance `R=(V)/(I)`, whereV=`100pm5V and I=10pm0.2A`. The pressure error in V is 5% and in I is 2%. What is the total percentage error in R?

Topper's Solved these Questions

PHYSICAL WORLD AND MEASUREMENTS
SL ARORA|Exercise problem|10 Videos
PHYSICAL WORLD AND MEASUREMENTS
SL ARORA|Exercise problem for self practice|64 Videos
Physical world
SL ARORA|Exercise Exercise|49 Videos
PROJECTILE MOTION
SL ARORA|Exercise Problem For Self Practice|50 Videos

Similar Questions

Explore conceptually related problems

The resistance R= (V)/(I) , where V= (100+-5.0) V and I=(10+-0.2)A . Find the percentage error in R .

The resistance R = (V )/(i) , where V=(50 pm 2.0)V and I=(20pm 0.2)A. The percentage error in R is ’x’% The value of 'x' to the nearest integer is "_________"

The resistance R = V//i , where V = 100 +- 5 V and I = 10+- 0.2 A . What is the total error in R ?

The resistance R=(V)/(I) where V=(200+-5)V and I=(20+-0.2)A ,the percentage error in the measurement of "R" is :

If voltage V=(100pm5) V and current I=(10pm0.2) A, the percentage error in resistance R is

The resistance of a conductor R = V//I , where V = (50 +- 2) V and I = (9 +- 0.3) A . Find the percentage error in R .

In a simple pendulum l=(100.0pm0.5) cm and t=(2.00pm0.01) sec. What is the percentage error in g?

The error in the measurement of the length of a simple pendulum is 0.1% and the error in the time period is 2% . What is the possible percentage of error in the physical quantity having the dimensional formula LT^(-2) ?

The resistance of metal is given by V = IR , The voltage in the resistance is V = (8 pm 0.5)V and current in the resistance is I = (2 +- 0.2)A , the value fo resistance with its percentage error is

SL ARORA-PHYSICAL WORLD AND MEASUREMENTS-Based on Combination

The resistance R=(V)/(I), whereV=100pm5V and I=10pm0.2A. The pressure ...
Text Solution
|
The length of two rods are recorded as l(1) = (25.2 pm 0.1) cm and l(2...
Text Solution
|
Two resistance (200 pm 4) Omega and (150 pm 3) Omega are connected in ...
Text Solution
|
The initial and final temperature of water were recorded as (56.3 pm 0...
Text Solution
|
If l(1) = (10.0 pm 0.1) cm and l(2) = (9.0 pm 0.1) cm , find the their...
Text Solution
|
A capacitor C = (2.0 +- 0.1)muF is charged to a voltage V = (20 +- 0.5...
Text Solution
|
The resistance R of a conductor is defind as the ratio of the potentia...
Text Solution
|
The relative density of a material is found by weighing the body first...
Text Solution
|
The length and breadth of a rectangular block are 25.2 cm and 16.8 cm,...
Text Solution
|
While measuring the volume of a sphere , an error of 1.2 % is commited...
Text Solution
|
The voltage across a lamp is (6.0 +- 0.1) V and the current passing th...
Text Solution
|
The radius of a sphere is measured to be (2.1+-0.5) cm. Calculate its ...
Text Solution
|
The radius of a sphere is (5.3 +- 0.1)cm The perecentage error in its ...
Text Solution
|
The measure of the diameter of a cylinder is (1.60 pm 0.01) cm and it...
Text Solution
|
The measured mass and volume of a body are 2.00 g and 5.0 cm^(3) respe...
Text Solution
|
Two resistance R(1) and R(2) are connected in (i) series and (ii) para...
Text Solution
|
A body travels uniformly a distance of ( 13.8 +- 0.2) m in a time (4.0...
Text Solution
|
The centripetal force acting on a body of mass m moving with speed v a...
Text Solution
|
The period of oscillation of a simple pendulum is T = 2 pi sqrt((L)/(g...
Text Solution
|
Calculate the percentage error in specific resistance , rho = pi r^(2)...
Text Solution
|
The Young's modulus Y is determined by stretching a wire by using the...
Text Solution
|