To find the value of 'g' by using a simple pendulum, the following observations were made: Length of the thread, `I =(100+- 0.1)cm` Time period of oscillation, `T = (2+-0.1)s` Calculate the maximum permissible in measurement of 'g' which quanitiy should be measured more accurately and why ?

In an experiment for determining the value of acceleration due to gravity (g) using a simpe pendulum , the following observations were recorded: Length of the string (l) = 98.0 cm Diameter of the bob (d) = 2.56 cm Time for 10 oscillations (T) = 20.0 s Calculate the value of g with maximum permissible absolute error and the percentage relative error.

In the measurement of g using a simple pendulum, which quantity should be measured which quantity should be measured with maximum accuracy and why ?

In determination of value of acceleration due to gravity (g) by simple pendulum, the time period is measured by a topwatch (L.C. = 0.5 second) and length of the thread is measured with metre scale (L.C. 0.1 cm) and diametre of bob is measured with vernier callipers (L.C. = 0.1 cm). The following observations are recorded : Length of the thread =105.3 cm Diameter of the bob =2.45 cm Time period =2.07 s Number of oscillations =10 Calculate the value of g, estimate error and write the result in proper significant figures.

In an experiment of simple pendulum, the errors in the measurement of length of the pendulum (L) and time period (T) are 3% and 2% respectively. The maximum percentage error in the value of L//T^(2) is

To find the value of g using simple pendulum , T = 2.00 s and l = 1.00 m were measured . Estimate maximum permissible error in g . Also find the value of g .

In an experiment of simple pendulum , the time period measured was 50 s for 25 vibrations when the length of the simple pendulum was taken 100 cm . If the least count of stop watch is 0.1 s and that of meter scale is 0.1 cm . Calculate the maximum possible error in the measurement of value of g . If the actual value of g at the place of experiment is 9.7720 m s^(-2) , Calculate the percentage error.

To find the value of g using simple pendulum. T=2.00 sec , 1=1.00m was measured. Estimate maximum permissible error in g . (use pi^(2)=10 )

In an experiment of simple pendulum, time period measured was 50s for 25 vibrations when the length of the simple pendulum was taken to be 100cm . If the lest count of stop watch is 0.1s and that of metre scale is 0.1 cm , calculate the maximum possible percentage error in the measurement of value of g .

Which is more precise measurement of the length of a thread (i) 10.0 cm (ii) 10.00 cm ?