The velocity of a freely falling body is a function of the distance fallen through (h) and acceleration due to gravity g . Show by the method of dimensions that `v = Ksqrt(gh)` .

The velocity of a freely falling body changes as g^ph^q where g is acceleration due to gravity and h is the height. The values of p and q are

The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as it reaches the ground is

For an object at infinite distance from the earth, the value of acceleration due to gravity (g) is

The velocity of water wave v may depend on their wavelength lambda , the density of water rho and the acceleration due to gravity g . The method of dimensions gives the relation between these quantities as

The velocity of water waves (v) may depend on their wavelength lamda , the density of water rho and the acceleration due to gravity g. The method of dimensions gives the relation between these quantities as v^(2)=kg^(x)lamda^(x)rho^(y) . The value of x is (Here k is a constant).

What is the effect of mass of the body on acceleration due to gravity (g)?

Assertion : The time period of a freely falling pendulum is infinite. Reason : The effective value of acceleration due to gravity becomes zero.

If G is the universal constant of gravitation and g is the acceleration due to gravity, then the dimensions of (G)/(g) are

A body is released fro certain height, After falling for sometime. If acceleration due to gravity vanishes, then.

A body falls freely from a height 'h' after two seconds if acceleration due to gravity is reversed the body