Home
Class 11
PHYSICS
A body of mass m hung at one end of the ...

A body of mass `m` hung at one end of the spring executes simple harmonic motion . The force constant of a spring is `k` while its period of vibration is `T`. Prove by dimensional method that the equation `T = 2 pi m // k` is correct. Dervive the correct equation , assuming that they are related by a power law.

Text Solution

Verified by Experts

The correct Answer is:
`T = K sqrt(m//k)`
Promotional Banner

Topper's Solved these Questions

  • PHYSICAL WORLD AND MEASUREMENTS

    SL ARORA|Exercise Based on Significant|15 Videos
  • PHYSICAL WORLD AND MEASUREMENTS

    SL ARORA|Exercise Based on Errors in Measurements|3 Videos
  • PHYSICAL WORLD AND MEASUREMENTS

    SL ARORA|Exercise problem for self practice|64 Videos
  • Physical world

    SL ARORA|Exercise Exercise|49 Videos
  • PROJECTILE MOTION

    SL ARORA|Exercise Problem For Self Practice|50 Videos

Similar Questions

Explore conceptually related problems

A body of mass 20 g connected to a spring of spring constant k, executes simple harmonic motion with a frequency of (5//pi) Hz. The value of spring constant is

A particle at the end of a spring executes simple harmonic motion with a period t_1 , while the corresponding period of another spring is t_2 . If the period of oscillation with the two springs in series is T. Then

A particle at the end of a spring executes simple harmonic motion with a period t_(1) while the corresponding period for another spring is t_(2) if the oscillation with the two springs in series is T then

A paricle of mass 200 g executes a simple harmonic motion. The restorting force is provided by a spring of spring constant 80 N//m . Find the time period.

A mass m is suspended from the two coupled springs connected in series. The force constant for springs are k_(1) "and" k_(2). The time period of the suspended mass will be

A mass m is suspended from the two coupled springs connected in series. The force constant for spring are k_(1) and k_(2) . The time period of the suspended mass will be:

A block of mass 2kg executes simple harmonic motion under the reading from at a spring .The angular and the time period of motion are 0.2 cm and 2pi sec respectively Find the maximum force execute by the spring in the block.

A 0.20kg object mass attached to a spring whose spring constant is 500N/m executes simple harmonic motion. If its maximum speed is 5.0m/s, the amplitude of its oscillation is

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Fnd the maximum force exerted by the spring on the block.

A mass m oscillates with simple harmonic motion with frequency f= omega/(2pi) and amlitude A on a spring with constant K. therefore