A particle of mass 100 g is fired with a velocity of `20 ms^(-1)` making an angle of `30^(@)` with horizontal. When it rises to the point of its highest point, find the change in its momentum.

A projectile of mass 100 g is fired with a velocity of 20 ms^(-1) making an angle of 30^@ with the borizontal. As it rises to the highest point of its path its momentum changes by .

A particle of mass m is projected with velocity upsilon making an angle of 45^(@) with the horizontal When the particle lands on the level ground the mag nitude of the change in its momentum will be .

A particle of mass 'm' is projected with a velocity upsilon making an angle of 30^(@) with the horizontal. The magnitude of angular moment of the projectile about the point of projection when the particle is at its maximum height 'h' is

A particle of mass "m" is projected with a velocity ' "u" ' making an angle of 30^(@) with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height "h" is :

A body of mass 2 kg is projected at 20 ms^(-1) at an angle 60^(@) above the horizontal. Power due to the gravitational force at its highest point is

A particle of mass m is projected with a velocity mu at an angle of theta with horizontal.The angular momentum of the particle about the highest point of its trajectory is equal to :

A body is projected at an angle of 30^(@) with the horizontal with momentum P .At its highest point the magnitude of the momentum is:

A particle of mass m is projected with a velocity v making an angle of 45^@ with the horizontal. The magnitude of the angular momentum of the projectile abut the point of projection when the particle is at its maximum height h is.