A particle is projected with velocity `2 sqrt(gh)` so that it just clears two walls of equal height h which are at a distance 2h from each other. Show that the time of passing between the walls is `2 sqrt(h//g)`.

A particle is projected with velocity 2 sqrt(gh) so that it just clear two walls of equal height h , which are at a distance of 2h from each other . What is the tiime interval of passing between the two walls ?

An object is projected so that it just clears two walls of height 7.5 m and with separation 50m from each other. If the time of passing between the walls is 2.5s, the range of the projectile will be (g= 10m//s^(2) )

A particle is projected from ground with velocity 40sqrt(2)m//s at 45^(@) . At time t=2s

A particle is projected from ground with velocity 40sqrt2m at 45^(@) .At time t=2s

A particle is projected with a velocity u from a point at ground level. Show that it cannot clear a wall of height h at a distance x from the point of projection if u^2 lt g(h+sqrt(h^2+x^2)) .

A particle is projected from the ground at t = 0 so that on its way it just clears two vertical walls of equal height on the ground. The particle was projected with initial velocity u and at angle theta with the horiozontal. If the particle passes just grazing top of the wall at time t = t_1 and t = t_2 , then calculate. (a) the height of the wall. (b) the time t_1 and t_2 in terms of height of the wall. Write the expression for calculating the range of this projectile and separation between the walls.