A force F=a+b x acts on a particle in the X-direction, where a and b are constants. Find the work done by this force during a displacement from x=0 to x=d/

A force F=a+bx acts on a particle in the x-directioin, where a and b are constants. Find the work done by this force during a displacement form x=0 to x=d .

A force F=a+bx acts on a particle in x-direction, where a and b are constants. Find the work done by this force during the displacement from x_1 to x_2 .

A force F=(a+bx) acts on a particle in x direction where a and b are constants . Find the work done by this force during displacement from x_(1) to x_(2) .

A force F=(5+2x) acts on a particle in x direction where F is in newtown and x is meter. Find the work done by this force during displacement from x=0 to x=1m.

A force F=(15+0.50x) acts on a particle in the X-direction ,where F is in newton and x in metre Find the work done ' by this force during a displacement from x=0 to x=2.0 m .

A force F=(2+x) acts on a particle in x-direction where F is in newton and x in metre. Find the work done by this force during a displacement form 1. 0 m to x = 2.0 m.

A force F=(10+0.50x) acts on a particle in the x direction, where F is in newton and x in meter./find the work done by this force during a displacement form x=0 tox=2.0m

A force F=(10+0.5 x) acts on a particle in the x-direction. What would be the work done by this force during a displacement from x=0 to x=2m (F is in newton and x in metre)

A force F = p+qx acts on a particle in the X - direction , where p and q are constants . If the particle is displaced from x = a to x = b , find the work done by the force .

A force F = (10 +0.25x ) is acting on a particle moving along positive X direction . Calculate the work done by this force during a displacement from x = 1 m to x = 4 m .