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A ball falls under gravity from a hight ...

A ball falls under gravity from a hight of 10 m height of 10 m wioth an initial downward velocity u .If collides with the gound , loses `50%` of its energy in collision and then rises back back to the same heighrt .Find the initial velocity u.

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Knowledge Check

  • A ball falls under gravity from a height of 10 m with an initial downward velocity u. It collides with the ground, losses 50% of its energy in collision and then rises back to the same height. The initial velocity u is

    A
    `7 m s^(-1)`
    B
    `25 m s^(-1)`
    C
    `14 m s^(-1)`
    D
    `28 m s^(-1)`
  • A ball falls under gravity from a height 10 m with an initial velocity v_0 . It hits the ground, loses 50% of its energy in collision and it rises to the same height, what is the value of v_0 ?

    A
    14 m/s
    B
    7 m/s
    C
    28 m/s
    D
    9.8 m/s
  • A ball is thrown vertically downwards from a height of 20 m with an initial velocity v_0 . It collides with the ground, loses 50 percent of its energy in collision and rebounds to the same height. The initial velocity v_0 is (take g = 10 ms^(-2))

    A
    `28 ms^(-1)`
    B
    `10 ms^(-1)`
    C
    `14 ms^(-1)`
    D
    `20 ms^(-1)`
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    A tennis ball is thrown from a height h with an initial downward velocity u. It rebounces back to the same height after losing half of its KE.The value of u is

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    A ball is thrown vertically downwards from a height of 20m with an intial velocity v_(0) . It collides with the ground, loses 50% of its energy in collision and rebounds to the same height. The intial velocity v_(0) is (Take, g =10 ms^(-2) )

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    A ball is thrown vertically down from height of 40 m from the ground with an initial velocity 'v'. The ball hits the ground, loses (1)/(3)rt of its total mechanical energy and rebounds back to the same height. If the acceleration due to gravity is 10 "ms"^(-2) , the value of 'v' is