A body having masss oif 100g is allowed to fall freely under the action of gravity. Calcualate the kinetic energy after 10s. Take g=`9.8ms^(-2)`.

A body of masss 1kg is allowed to fall freely under gravity. Find the mimimum and kinetic energy of the body 5 second after it starts falling. Take g= 10 ms^(-2)

Calculate the mass of a body weighing 100 dyne . Take g = 10 ms^(-2) .

Matching type Question : A ball thrown up is caught by the thrower after 4s. Take g = 9.8 ms^(-2) .

Potential energy of a body is the energy possessed by the body by virtue of its position. P.E. =mgh where the symbols have their usual meaning. Kinetic energy of a body is the energy possessed by the body by virtual of its velocity. K.E.=(1)/(2)m upsilon^(2) Energy can neither be created nor be destroyed. However energy can be changed from one form to other, such that energy appearing in one form is equal to the energy disappearing in the other form. With the help of the passage given above, choose the most appropriate alternative for each of the following question : A body of mass 1 kg is allowed to fall freely under gravity. The momentum of the body 5 second after it starts falling is

Ball of mass 5 kg is allowed to fall from the highest point of a tower which is 490 m high. Calculate the time it will take to hit the ground ? (g=9.8m//s^2)

A body of mass 0.05 kg is observed to fall with an acceleration of 9.5ms^(-2) . The opposing force (in newton) of air on the bod is ( g=9.8ms^(-2) )

Find the momentum of a body of mass 100 g having a kinetic energy of 20 J.

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. (g=9.8m//s^(2))

From the top of a tower, a ball is droped to fall freely under gravity and at the same time, another bal is thrown up with a velocity of 50 ms^(-1) . Plot the position-time graph for the motion of the two balls during the time interval t = 0 to t = 5s. Take g = 10 ms^(-2)