A body of masss 1kg is allowed to fall freely under gravity. Find the mimimum and kinetic energy of the body 5 second after it starts falling. Take g=`10 ms^(-2)`

Potential energy of a body is the energy possessed by the body by virtue of its position. P.E. =mgh where the symbols have their usual meaning. Kinetic energy of a body is the energy possessed by the body by virtual of its velocity. K.E.=(1)/(2)m upsilon^(2) Energy can neither be created nor be destroyed. However energy can be changed from one form to other, such that energy appearing in one form is equal to the energy disappearing in the other form. With the help of the passage given above, choose the most appropriate alternative for each of the following question : A body of mass 1 kg is allowed to fall freely under gravity. The momentum of the body 5 second after it starts falling is

A body having masss oif 100g is allowed to fall freely under the action of gravity. Calcualate the kinetic energy after 10s. Take g= 9.8ms^(-2) .

A body of mass 10 kg is dropped from a height of 10 m on a planet, whose mass and radius are double that of the Earth. Find the maximum kinetic energy the body can possess. ("Take" g_(E) = 10 ms^(-2))

A body, freely falling under gravity will have uniform

A body starts to fall freely under gravity. The distances covered by it in first, second and third second are in ratio

A body of mass 5kg initially at rest, is subjected to a force of 40 N. Find the kinetic energy acquired by the body at the end of 5 seconds :

A force fo 3000 dyne acts on a body of mass 400g for 10s. Find the kinetic energy of the body after 10s.

A body falling freely under gravity passes two points 30 m apart in 1 s. From what point above the upper point it began to fall? (Take g = 9.8 m s^(-2) ).

Ratio of distances covered by object falling freely under gravity in 1^(st) , 2^(nd) and 3^(rd) second is