A pump can throw up 10 quntals of coal per hour from a coal mine `120m` deep. Calculate the power of the engine in watt assuming that efficiency is `80%`.

A pump can take out 7200 kg of water per hour from a well 100 m. deep. The power of pump, assuming its efficiency as 50% will be

An engine pumps up 1 quintal of coal from a coal mine 100 m deep in 0.5 seocnd. If its efficienty is 60% then the power of the engine is (take g=10m//s^(2))

An engine pumps 800 kg of water through height of 10 m in 80 s. Find the power of the engine if its efficiency is 75%

A 1-KW motor pumps out water from a well 10m deep. Calculate the quantity of water pumped out per second.

An engine pumps 400 kg of water through height of 10 m in 40 s. Find the power of the engine if its efficiency is 80% (Take ,g =10 ms^(-2) ).

A pump is required to lift 1000 kg of water per minute from a well 20 m deep and ejects at a speed of 20 m/s. The power of engine is

A pump of power 20 kW is used to jump out the water from a well 12 m deep . Calculate the efficiency of the pump if 5,000 kg of water is pumped out in 1 minute .

Calculate the power of an engine required to lift 10^5 kg of coal per hour from a mine 360 m deep.