Find the angle through which a cyclist bends when he covers a circular path `34.3 m` long in `sqrt (22)` sec . Given `g = 9.8 ms^(-2)` .

A body weighing 0.4 kg is whirled in a vertical circle making 2 revolutions per second. If the radius of the circle is 1.2 m, find the tension in the string, when the body is (a) at the top of the circle (b) at the bottom of the circle. Given : g = 9.8 ms^(-2) and pi = 1.2 m

Find the angle of elevation of the Sun when the shadow of a pole h m high is sqrt(3)m long.

A stone of mass 0.3 kg is tied to one end of a string 0.8 m long and rotated in a vertical circle. At what speed of the ball will the tension in the string be zero at the highest point of the circle? What would be the tension at the lowest point in this case ? Given g = 9.8 ms^(-2) ?

The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3 m without skidding is ("Take g"=10ms^(-2))

A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in sqrt(22) second. The angle made by him, with the vertical, will be:-

Why does a cyclist lean inward when moving along a curved path?Determine the angle through which a cyclist bends from the vertical while negotiating a curve.

A cricket ball is rolled on ice with a velocity of 5.6 m//s and comes to rest after travelling 8 m . Find the coefficient of friction Given g = 9.8 m//s^(2) .

A body is mass 300 kg is moved through 10 m along a smooth inclined plane of inclination angle 30^@ . The work done in moving (in joules) is (g = 9.8 ms^(-2)) .

A ball rolled on ice with a velocity of 14 ms^(-1) comes to rest after travelling 40 m . Find the coefficient of friction . (Given g = 9.8 m//s^(2)

A body rolled on ice with a velocity of 8 ms^(-1) comes to rest after travelling 4 m. Compute the coefficient of friction. Given g= 9.8 ms^(-2)