Calculate rotational `K.E.` of earth about its own axis, taking it to be a sphere of mass `6 xx 10^(24) kg` and radius `6400 km`.

Calculate the moment of inertia of the earth about its diameter, taking it to be a sphere of 10^(25) kg and diameter 12800 km.

Calculate angular momentum of earth rotating about its axis. Take I = (2)/(5)MR^(2) , where M = 6 xx 10^(24) kg and R = 6400 Km .

Calculate the angular momentum of the earth rotating about its own axis. Mass of the earth = 5.98 xx 10^(27) kg, mean radius of the earth =6.37 xx 10^(6)m,M.I of the earth = (2)/(5)MR^(2) .

The earth circles the sun once a year. How much work would have to be done on the earth to bring it to rest relative to the sun, (ignore the rotation of earth about - its own axis) Given that mass of the earth is 6 × 10^(24) kg and distance between the sun and earth is 1.5 × 10^(8) km-

A geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of the satellite ? Mass of the earth= 6xx10^(24) kg and radius =6400 km.

Calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground.(Mass of earth =6xx10^(24) kg Radius of earth =6.4xx10^(3) km and G=6.7xx10^(-11)Nm^(2)/Kg^(2)

A geostationary satellite orbits the Earth at a height of nearly 36,000 km from the surface of earth. What is the potential due to earth's gravity at the site of tthis satllite ? (Take the potential energy at infinity to be zero). Mass of the Earth = 6.0 xx 10^(24) kg , radius = 6400 km, G = 6.67 xx 10^(-11) Nm^(2)//kg^(2) .

The earth rotates about its own axis, then the value of acceleration due to gravity is

Calculate the angular momentum of earth rotating about its own axis. Take Radius of earth =6.4xx10^(6)m Mass of earth =5.97xx10^(24)kg