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How much tangential force would be neede...

How much tangential force would be needed to stop the earth in one year, if it were rotating with angular velocity of `7.3 xx 10^(-5) "rad s"^(-1)` ? Given the moment of inertia of the earth `=9.3 xx 10^(37) "kg m"^(2)` and radius of the earth `=6.4 xx 10^(6)` m.

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How much tangential force will be needed to stop the earth in one year, if it is rotating with an angular velocity of 7.3 xx 10^(-5) rad//s ? Given moment of inertia of earth = 9.3 xx 10^(37) kg m^(2) and radius of earth = 6.4 xx 10^(6) m .

Calculate the acceleration due to gravity on the earth from the following data G= 6.6 xx 10 ^(-11) N m^(2) Kgm^(-3) Mean density of the earth = 5xx 10 ^(-3) kgm Radius of the earth = 6.4 xx10 ^(6) m .

The earth (mass = 10^(24) kg) revolves round the Sun with an angular velocity 2 xx 10^(-7) rad s^(-1) in a circular orbit of radius 1.5 xx 10^(8)km . Find the force exerted by the Sun on the earth (in xx 10^(21)N) .

Give the order of the following : Mean radius of earth ( 6.37xx10^(6)m )

Calculate the angular momentum of the earth rotating about its own axis. Mass of the earth = 5.98 xx 10^(27) kg, mean radius of the earth =6.37 xx 10^(6)m,M.I of the earth = (2)/(5)MR^(2) .

What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is 6xx10^(24) kg and radius of the Earth is 6.4xx10^(6) m) .

Calculate the speed of projection necessary to send a body right out of the filed of the earth's grvivtational attraction. G= 6.63 xx10^(-11) "newton metre^(2) " Kg^(2) Mass of the earth = 5.97 xx 10^(24) Radius of the earth = 6.37 xx 10^(6) m .

How much energy will be needed for a body of mass 100kg to escape from the earth- (G = 10M//S^(2) and radius of earth = 6.4 xx 10^(6) m)

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