From a uniform circular disc of diameter D, a circular disc or hole of diameter `D//6` and having its centre at a distance of `D//4` from the centre of the disc is scopped out. Determine the centre of mass of the remaining portion.

From a uniform circular disc of diameter d,a circular disc of diameter d//6 and having centre at a distance d//4 from the centre of the disc is scooped out. Determine the centre of mass of remaining portion.

From a uniform circular dis of radius R , a circular dis of radius R//6 and having centre at a distance R//2 from the centre of the disc is removed. Determine the centre of mass of remaining portion of the disc.

Find the centre of mass of the shaded portion of a disc.

A circular disc of radius (R)/(4) is cut from a uniform circular disc of radius R. The centre of cut portion is at a distance of (R)/(2) from the centre of the disc from which it is removed. Calculate the centre of mass of remaining portion of the disc.

From a uniform disc of radius R , a circular section of radius R//2 is cut out. The centre of the hole is at R//2 from the centre of the original disc. Locate the centre of mass of the resulating flat body.

From a circular disc of radius R , a triangular portion is cut (sec figure). The distance of the centre of mass of the remainder from the centre of the disc is -

A uniform circular disc of radius a is taken. A circular portion of radius b has been removed from it as shown in the figure. If the center of hole is at a distance c from the center of the disc, the distance x_(2) of the center of mass of the remaining part from the initial center of mass O is given by

A circular plate of uniform thickness has a diameter fo 56cm. A circular portion of diameter 42 cm is removed from one edge of the plate as shown in figure. Find the position of the centre of mass of the remaining portion.