Determine the angular momentum of a car of mass 1500 kg moving in a circuit truck of radius 50 m with a speed of `40 ms^(-1)`.

Answer

To determine the angular momentum of a car moving in a circular track, we can use the formula for angular momentum (L) given by:

\[ L = m \cdot v \cdot r \]

where:
- \( L \) is the angular momentum,
- \( m \) is the mass of the car,
- \( v \) is the linear velocity of the car,
- \( r \) is the radius of the circular path.

### Step-by-step Solution:

1. **Identify the given values:**
- Mass of the car, \( m = 1500 \, \text{kg} \)
- Speed of the car, \( v = 40 \, \text{m/s} \)
- Radius of the circular track, \( r = 50 \, \text{m} \)

2. **Substitute the values into the angular momentum formula:**
\[ L = m \cdot v \cdot r \]
\[ L = 1500 \, \text{kg} \cdot 40 \, \text{m/s} \cdot 50 \, \text{m} \]

3. **Calculate the product:**
- First, calculate \( 1500 \cdot 40 \):
\[ 1500 \cdot 40 = 60000 \, \text{kg m/s} \]
- Now multiply this result by the radius \( 50 \):
\[ L = 60000 \, \text{kg m/s} \cdot 50 \, \text{m} = 3000000 \, \text{kg m}^2/\text{s} \]

4. **Express the final answer in scientific notation:**
\[ L = 3 \times 10^6 \, \text{kg m}^2/\text{s} \]

### Final Answer:
The angular momentum of the car is \( 3 \times 10^6 \, \text{kg m}^2/\text{s} \).

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