A mass `M` is broken into two parts of masses `m_(1)` and `m_(2)`. How are `m_(1)` and `m_(2)` related so that force of gravitational attraction between the two parts is maximum?
Topper's Solved these Questions
GRAVITATION
SL ARORA|Exercise Problem From Competitive Examinations|14 Videos
GRAVITATION
SL ARORA|Exercise Exercise|480 Videos
FLUIDS IN MOTION
SL ARORA|Exercise All Questions|117 Videos
HEAT
SL ARORA|Exercise Problem For Self Practice|72 Videos
Similar Questions
Explore conceptually related problems
Two bodies of masses m_1 and m_2(
Mass M is divided into two parts m_1 , and m_2 , For a given separation the ratio of m_1/M for which the gravitational attraction between the two parts becomes maximum is
Two particles of mass m_(1) and m_(2) , approach each other due to their mutual gravitational attraction only. Then
Mass M is divided into two parts x M and (1-x)M. For a given separation, the value of x for which the gravitational attraction between the two pieces becomes maximum is
The gravitational force between two particles of masses m_(1) and m_(2) separeted by the same distance, then the gravitational force between them will be
Two masses m_(1) and m_(2) ( m_(2) gt m_(1)) are hanging vertically over frictionless pulley. The acceleration of the two masses is :
Two masses m_(1) and m_(2)(m_(1)ltm_(2)) are released from rest finite distance. They start under their mutual gravitational attraction-
A bomb at rest explodes into two parts of masses m_(1) and m_(2) . If the momentums of the two parts be P_(1) and P_(2) , then their kinetic energies will be in the ratio of:
