Home
Class 11
PHYSICS
The Mount Everst is 8848 m above sea lev...

The Mount Everst is 8848 m above sea level. Estimate the accelleration due to gravity at this height, given that mean g on the surface of the earth is `9.8 ms^(-2)` and mean radius of the earth is `6.37xx10^(6)`m

Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    SL ARORA|Exercise Problem From Competitive Examinations|14 Videos

  • GRAVITATION

    SL ARORA|Exercise Exercise|480 Videos

  • FLUIDS IN MOTION

    SL ARORA|Exercise All Questions|117 Videos

  • HEAT

    SL ARORA|Exercise Problem For Self Practice|72 Videos

Similar Questions

Explore conceptually related problems

What is the acceleration due to gravity at a height h ( = radius of the earth) from the surface of the earth ? ltbgt (g=9.8m//s^(2))

The height at which the acceleration due to gravity becomes (g)/(9) (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :

The height at which the acceleration due to gravity becomes (g)/(9) (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth is

At what altitude, the acceleration due to gravity reduces to half of its value as that on the surface of the earth ? Take radius of earth as 6.410^(6) m, g on the surface of the earth as 9.8 m//s^(2) .

The centripetal acceleration of a satellite that circles the earth at an altitude 400 km above see level is (g on the surface of earth is 10m//s^(2) , Radius of the earth is 6.4xx10^(6)m )

If R is the radius of the earth and g the acceleration due to gravity on the earth’s surface, the mean density of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

At what altitude, the acceleration due to gravity reduces to one fourth of its value as that on the surface of the earth ? Take radius of earth as 6.4 xx 10^(6) m , g on the surface of the earth as 9.8 ms^(-2) .

At what altitude , the acceleration due to gravity reduces to half of its value as that on the surface of the earth ? Take radius of earth as 6 . 4 xx 10^(6) m , g on the surface of the earth as 9.8 m//s ^(2) .

Give the order of the following : Mean radius of earth ( 6.37xx10^(6)m )