An earth's satellite makes a circle around the earth in 90 minutes. Calculate the height of the satellite above the earth's surface. Given radius of the earth is 6400 km and g=980 `cms^(-2)`
Topper's Solved these Questions
GRAVITATION
SL ARORA|Exercise Problem From Competitive Examinations|14 Videos
GRAVITATION
SL ARORA|Exercise Exercise|480 Videos
FLUIDS IN MOTION
SL ARORA|Exercise All Questions|117 Videos
HEAT
SL ARORA|Exercise Problem For Self Practice|72 Videos
Similar Questions
Explore conceptually related problems
An Earth's satellite makes a circule around the Earth in 100 minutes. Calculate the height of the satellite above the Earth's surface. Given the radius of the Earth is 6400 km g = 10 ms^(-2) . Use pi^(2) = 10 .
A satellite contructs a circle around the earth in 90 minutes. Determine the height of the satellite above the earth's surface.
An artificial satellite completes a circle around earth in 120 minutes. Calculate the height of the satellite above the earth's surface. Take, radius of earth = 6,400 km g = 9.8 m//s^(2)
Find the velocity of a satellite at height 80 km from earth. If the radius of earth is 6400 km
Calculate the height of the Apple (India's first geostationary satellite) above the surface of the earth (Radius of the earth = 6400 km and g = 9.8 ms^(-2) )
An artificial satellite circled around the earth at a distance of 3400 km. Calculate its orbital velocity and period of revolution. Radius of earth =6400 km and g=9.8 ms^(-2) .
A satellite circled around the earth at a distance of 100 km. Determine its orbital velocity, if the radius of the earth is 6400 km and g = 9.8 ms^(-2) .
A satellite of mass 10 kg is placed initially in a temporary orbit 800 km above the surface of earth. The satellite is to be placed now in a permanent orbit at 2000 km above the surface of earth. Find the amount of workdone to move the satellite from temporary to permanent orbit. The radius of the earth is 6400 km and g = 10 ms^(-2) .