Determine the escape speed of Moon. Given, the radius of Moon is `1.74 xx 10^(6) m`, its mass is `7.36 xx 10^(22) kg`. Does your answer throw light on why the moon has no atmosphere?
`G = 6.67 xx 10^(-11) n m^(2) kg^(-2)`.

The radius of the moon is 1.7 xx 10^(6) m and its mass is 7.35 xx 10^(22) kg . What is the acceleration due to gravity on the surface of the moon ? Given G = 6.67 xx 10^(-11) Nm^(2) kg^(-2).

The radius of the earth is 6.37xx10^(6) m its mass 5.98xx10^(24) kg determine the gravitational potential on the surface of the earth Given G=6.67 xx10^(-11) N-m^(2)//khg^(2)

Find the velocity of escape at the moon. Given that its radius is 1.7xx10^(6) m and the value of 'g' is 1.63 ms^(-2) .

What would be the escape velocity from the moon, it the mass of the moon is 7.4 xx 10^(22) kg and its radius is 1740 km ?

Mass of earth is (5.97 xx 10 ^(24)) kg and mass of moon is (7.35 xx 10 ^(22)) kg. What is the total mass of the two ?

Mass of moon is 7.34xx10^(22)kg . If the acceleration due gravity on the moon is 1.4m//s^(2) , the radius of the moon (G=6.667xx10^(-11)Nm^(2)//kg^(2))

Determine the escape velocity of a planet with mass 3xx10^(25)"kg and radius" 9xx10^(6)m.

The radius of the moom is 1.7 xx 10^(6) m and its mass is 7.4 xx 10^(22) kg . If G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) , find the value of acceleration due to gravity on the surface of moon.

Mass of moon is 7.3 xx 10^(22) kg and its radius is 1.74 xx 10^(6) m. Find the value of the acceleration due to gravity on the moon.

The weight of a person on the surface of the Earth is 490 N. Find his weight on the surface of Jupiter and the moon. Also, compare it with his weight on the Earth. Mass of moon = 7.3 xx 10^(22) kg, Mass of Jupiter = 1.96 xx 10^(27) kg, Radius of moon = 1.74 xx 10^(6) m and radius of Jupiter = 7 xx 10^(7) m G = 6.67 xx 10^(-11) N m^(2) kg^(-2) ltBrgt Given, (1)/(1.742) = 0.33 "and ge" = 9.8 m s^(-2)