The radius of a planet is double that of the earth but then average densities are the same. If the escape velocities at the planet and at the earth are `v_(P)` and `v_(E)` respectively, then prove that `v_(P)=2 v_(E).`

The radius of a planet is twice that of the earth but its average density is the same. If the escape speed at the planet and at the earth are v_(p) and v_(e) , respectively, then prove that v_(p)=2v_(e)

The radius of a planet is 1/4th of Re and its acc. due to gravity is 2g. What would be the value of escape velocity on the planet, if escape velocity on earth i v_(e)

The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. It's the escape velocity from the earth is v , then the escape velocity from the planet is:

Acceleration due to gravity on a planet is 10times the value on the earth . Escape velocity for the planet and the earth are V_(f) and V_(e) respectively Assuming that the radii of the planet and the same then

Planet A has massa M and radius R. Planet B has half the mass and half the radius of Planet A.If the escape velocities from the Planets A and B are v_(A) and v_(B), respectively , then (v_(A))/(v_(B))=n/4. The vlaue of n is :

Acceleration due to gravity on a planet is 10 times the value on the earth. Escape velocity for the planet and the earth are V_(p) and V_(e) respectively. Assuming that the radii of the planet and the earth are the same, then -

The escape velocities of the two planets, of densities rho_1 and rho_2 and having same radius, are v_1 and v_2 respectively. Then

The mass of a planet is half that of the earth and the radius of the planet is one fourth that of the earth. If we plan to send an artificial satellite from the planet, the escape velocity will be (V_(e)=11 kms^(-1))

The acceleration due to gravity on a planet is same as that on earth and its radius is four times that of earth. What will be the value of escape velocity on that planet if it is v_(e) on earth