A rocket is fired fired vertically from the surface of Mars with a speed of 2 `Kms^(-1)`. If `20%` of its initial energy is lost due to martain atmospheric resistance, how far will the rocket go from the surface of Mars before returning to it ? Mass of Mars=`6.4xx10^(23)`Kg, radius of Mars=3395 Km, G=`6.67xx10^(-11)Nm^(2)Kg^(-2)`.
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A rocket is fired vertically from the surface of Mars with a speed of 2kms^(-1) . If 20% of its initial energy is lost due to Martian atmospheric resistance, how far will the rocket go from the surface of Mars before returning to it? Mass of Mars =6.4xx10^(23)kg , radius of Mars =3395 km ,
A rocket is fired vertically from the surface of mars with a speed of 2 km/s. If 20% of its initial energy is lost due to martian atmosphere resistance how far (in km) will the rocket go from the surface of mars before returning to it? Mass of mars =6.4xx10^(23) kg, radius of mars =3395 km, G=6.67xx10^(-11)Nm^(2)//kg^(2) .
A rocket of mass m is field vertically from the surface of Mars of mass M , radius R with a sped upsilon . If 20% of its initial energy is lost due to Martain atmosheric resistance, how far will the rocket go from the surface of Mars before returing to it? Let G be the gravational constant.
A rocket is fired vertically with a speed of 5 kms^(-1) from the earth's surface. How far from the earth does the rocket go before returning to the earth ? Mass of earth= 6.0xx10^(24) kg, mean radius of the earth = 6.4xx10^(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2).
Calculate the escape speed of a body from the surface of a planet of mass 6.4 xx 10^(23) kg and radius 3400 km.
A body is projected vertically upwards from the surface of the Earth so as to reach a height equal to the radius of the Earth. Neglecting resistance due to it, calculate the initial speed which should be imparted to the body. Mass of Earth = 5.98 xx 10^(24) kg , Radius of Earth = 6400 km , G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .
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