A rocket in launched vertically from the sruface of earth with an initial velocity u. Find the height up to which the rocket can go from the surface velocity u. Find t eh height up to which the rocket can go from the surface of earth before back or earth

A rocket is launched vertically from the surface of earth with an initial velocity v . How far above the surface of earth it will go? Neglect the air resistance.

The escape velocity of a rocket launched from the surface of the earth

A rocket is launched vetically from the surface of the earth with an initial velocity of 10 kms^(-1) . How for above the surface of the earth would it go ? Radius of the earth =6400 km and g=9.8 ms^(-2) .

A rocket of mass M is launched vertically from the surface of the earth with an initial speed V= sqrt((gR)/(2)) . Assuming the radius of the earth to be R and negligible air resistance, the maximum height attained by the rocket above the surface of the earth is (R)/(X) where X is:

A rocket is launched vertical from the surface of the earth of radius R with an initial speed v . If atmospheric resistance is neglected, then maximum height attained by the rocket is

A particle is throws vertically upwards from the surface of earth and it reaches to a maximum height equal to the radius of earth. The radio of the velocity of projection to the escape velocity on the surface of earth is

A body is projected vertically upwards from the surface of the earth with a velocity equal to half of escape velocity of the earth. If R is radius of the earth, maximum height attained by the body from the surface of the earth is

For a body thrown vertically up with an initial velocity u ,the maximum height reached by body from the ground is