Home
Class 11
PHYSICS
A rocket is launched vetically from the ...

A rocket is launched vetically from the surface of the earth with an initial velocity of 10 `kms^(-1)`. How for above the surface of the earth would it go ? Radius of the earth =6400 km and `g=9.8 ms^(-2)`.

Text Solution

Verified by Experts

The correct Answer is:
`2.5xx10^(4)` km
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    SL ARORA|Exercise m|1 Videos
  • GRAVITATION

    SL ARORA|Exercise I: Based on Kepler s Law of Periods|6 Videos
  • FLUIDS IN MOTION

    SL ARORA|Exercise All Questions|117 Videos
  • HEAT

    SL ARORA|Exercise Problem For Self Practice|72 Videos

Similar Questions

Explore conceptually related problems

A rocket is launched vertically from the surface of earth with an initial velocity v . How far above the surface of earth it will go? Neglect the air resistance.

A projectile is launched vertically from earth's surface with an inittial velocity of 10 km/s. Calculate the height it will reach above the earth's surface. Take, Radius of earth = 6,400 km g = 9.8 m//s^(2)

A projectile is fired vertically from the earth's surface with an initial speed of 10 km//s . Neglecting air drag, how high above the surface of earth will it go?

If the value of g at the surface of the earth is 9.8 m//sec^(2) , then the value of g at a place 480 km above the surface of the earth will be (Radius of the earth is 6400 km)

The escape velocity of a rocket launched from the surface of the earth

How much below the surface of the earth does the acceleration due to gravity become 70% of its value at the surface of the earth ? Radius of the earth is 6400 km

Calculate the height of the Apple (India's first geostationary satellite) above the surface of the earth (Radius of the earth = 6400 km and g = 9.8 ms^(-2) )

Compare the weight of a body 100 km above and 100 km below the surface of the earth . Radius of the earth = 6400 km .

Aparticle is projected from the surface of the earth with an intial speed of 4.0 km//s .Find the maximum height attained by the particle. Radius of earth = 6400km g = 9.8 m//s^(2) .