Two forces `vec(F)_(1) = 3hati +4hatj` and `vec(F)_(2) = 3hatj +4hatk` are acting simultaneously at a point. What is the magnitude of the resultant force ?

Two forces vecF_(1) = 2hati + 2hatj N and vecF_(2) = 3hati + 4hatkN are acting on a particle (a) Find the resultant force acting on particle (b) (b) Find the angle between vec(F_1) & vec(F_2) (c) Find the componant of force vec(F_1) along force vec(F_2) .

Three forces vec F_(1) =5hati+6hatj+7hatk, vec F_(2) =-3hati-2hatj-2hatk and vec F_(3) =-2hati-4hatj-3hatk act on a body. What is the direction of the resultant force acting on the body ?

Three forces vecF_(1)=(3hati+2hatj-hatk) dynes, vecF_(2)=(3hati+4hatj-5hatk) dynes and vecF_(3)=a(hati+hatj-hatk) dynes act simultaneously on a particle. What should be the value of 'a' so that the particle may remain in equilibrium?

A force vec(F) = 5hati + 4hatj newton displaces a body through vec(S) = 3hati +4 hatk metre in 3s. Find the power.

Two forces f_(1)=3hati-2hatj+hatk and f_(2)=hati+3hatj-5hatk acting on a particle at A move it to B. find the work done if the position vector of A and B are -2hati+5hatk and 3hati-7hatj+2hatk .

A force is represented by 2hati + 3hatj + 6hatk . The magnitude of the force is ………..

A body is moving under the action of two force vec(F_(1))=2hati-5hatj , vec(F_(2))=3hati-4hatj . It's velocity will become uniform under a third force vec(F_(3) given by.

Three forces hati+2hatj-3hatk,2hati+3hatj+4hatk and hati-hatj+hatk acting on a particle at the point (0,1,2) the magnitude of the moment of the forces about the point (1,-2,0) is