Home
Class 11
CHEMISTRY
If the anion (A) form hexagonal closet p...

If the anion (A) form hexagonal closet packing and cation (C ) occupy only 2/3 octahedral voids in it, then the general formula of the comound is:

A

CA

B

`CA_(2)`

C

`C_(2)A_(3)`

D

`C_(3)A_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|1 Videos
  • SOLID STATE

    NARENDRA AWASTHI|Exercise Level 3 - One Or More Answers Are Correct|1 Videos
  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Exercise|196 Videos
  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|20 Videos

Similar Questions

Explore conceptually related problems

If the anions (A) form hexagonal closest packing and cations (C ) occupy only 2/3 octahedral volids in it, then the general formula of the compound is:

If the anions (A) form hexagonal closest packing and cations (C) occupy only 2/3 octahedral voids in it. Then the general formula of the compound is

The anions A from hexagonal close packing and atoms (M) occupy only two-third of the octahedral voids. The general formula of the compound is

A compound is compound by cation C and anion A. The anions hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is

In a crystal of an ionic compound, the anions B form a close packed lattice and the cations A occupy one half of the tetrahedral voids. What is the formula of the compound ?

In a close packed structure of an ionic compound anions B form the close packed lattice and the cations A occupy octahedral voids.Predict the formula of the compound.