KCl crystallizes int the same type of lattic as done NaCl . Given that `r_(Na^(+))//r_(Cl^(-)) = 0.50` and `r_(Na^(+))//r_(K^(+)) = 0.70` , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:
A
`1.143`
B
`1.224`
C
`1.414`
D
`0.875`
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The correct Answer is:
A
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KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.
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KCI cyrstallizes in the saem type of lattice as does NaCl. Given that (r_(Na^(o+))/(r_(Cl_(-)))=0.5 and (r_(Na^(o+)))/(r_(K^(o+)))=0.7 Calculate the ratio of side of the unit cell for KCl to that for NaCl.
KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is
