A compound formed by elements A and B crystallises as FCC lattice. If A is present at the lattice points of unit cell and B occupy half of tetrahedral voids as well as one fourth of octahedral voids then the formula of the compound will be
In a crystalline solid, anions B are arranged in a ccp. Cations A are equally distributed between octahedral and tetrahedral voids. If all the octahedral voids are occupied, the formula of the compound is A_2B//A_3B .
Atoms A present in ccp lattice atoms B occupied tetrahedral voids and atoms C present in octahderal voids. The formula of compound is
In a compound, atoms A occupy 3//4 of the tetrahedral voids and atoms B from ccp lattice. The emperical formula of the compound is
In a binary compound, atoms of element A form a hcp structure and those of element Moccupy 2/3 of the tetrahedral voids of hcp structure. The formula of the binary compound is :
In a solid between A and B atoms of A are arranged in ccp array and atoms of B occupy all the octahedral voids and half of the tetrahedral voids. The formula of the compound is
In an ionic compound, oxide ions have ccp arrangement Cations A are present in one eighth of the tetrahedral voids whilst cations B occupy half of the octahedral voids.the empirical formula of the compound is