(sigma)/(1)=([6lc15+1)(sin15-1)],[(8500+1)(9500-1)]

(1)/(15)+(1)/(15)+(1)/(15) = ?

Sigma_(n=1)^(5)sin ^(-1) ( sin ( 2n -1)) is

Sigma_(n=1)^(5)sin ^(-1) ( sin ( 2n -1)) is

Sigma_(n=1)^(5)sin ^(-1) ( sin ( 2n -1)) is

Find: 3(1)/(6)-2(1)/(15)

The inverse of the matrix A[(1,1,1),(6,7,8),(6,7,-8)] using adjoint method is ...a) -(1)/(16)[(-112,1,15),(96,-14,-2),(0,-1,1)] b) -(1)/(16)[(-112,15,1),(96,-2,-14),(0,-1,1)] c) -(1)/(16)[(-112,15,1),(96,-14,-2),(0,-1,1)] d) -(1)/(16)[(112,15,1),(96,-14,-2),(-1,0,1)]

sin ^(-1)""(77)/(85) -cos^(-1)""(15)/(17)= sin ^(-1) ""(3)/(5)

Evaluate each of the following: sin((cot^(-1)4)/(3)) (ii) sin((sec^(-1)(17))/(15)) (iii) sin(csc^(-1)(17)/(8))