If 0.50L of a 0.60M `SnSo_4` solution is electrolysed for a period of 30.0min using a current of 4.60 A. If inert electrods are used, what is the final concentration of `Sn^(2+)` remaining in the solution?[at.mass of Sn=119]
A
0.342M
B
0.544M
C
0.389M
D
0.514M
Text Solution
Verified by Experts
The correct Answer is:
D
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
A 0.20 M KOH solution is electrolysed for 1.5h using a current of 8.00A . The number of moles of O_(2) produced at anode is
A current of 965A is passed for 1 s through 1L solution of 0.02N NiSO_(4) using Ni electrodes. What is the new concentration of NiSO_(4) ?
A current of 0.0965 ampere is passed for 1000 seconds through 50mL of 0.1M NaCl, using inert electrodes the average concentration of OH^(-) in the final solution is:
0.05M aqueous solution of NaCl is electrolysed. If a current of strength 0.5 amp is used for 193sec. The final concentration of Na^(+) ions in the electrolyte will be (volume of solution will be constant)
1 L of 0.1 M NaOH, 1 L of 0.2 M KOH , and 2 L of 0.05 M Ba (OH)_(2) are mixed togther. What is the final concentration of the solution.