Home
Class 11
CHEMISTRY
I(2)(s)|I^(-)(0.1M) half cell is connect...

`I_(2)(s)|I^(-)`(0.1M) half cell is connected to a `H^(+)` (aq)|`H_(2)`(1 bar)|Pt half celland e.m.f. is found to be 0.7714 V. If `E_(I_(2)|I^(-))^(@)`=0.535 V, find the pH of `H^(+)|H_(2)` half cell.

A

1

B

3

C

5

D

7

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

For the half-cell given Pt( H_(2) , 1 atm ) | H^+ pH = 2, the cell potential is :

For the cell Pt_((s)), H_(2) (1 atm)|H^(+) (pH=2)||H^(+) (pH=3)|H_(2) (1atm),Pt The cell reaction is

Given the cell: Cd(s)|Cd(OH)_2(s)|NaOH(aq,0.01M)|H_2(g,1"bar")|Pt(s) with E_(cell)=0.0V."if"E_(Cd^(2+)|Cd)^(@)=-0.39V,"then"K_(sp)"of"Cd(OH_2) is:

Construct at cell consisting of Ni_((ag))^(2+)| Ni_((s)) half cell and H^(+) ||H_(2(g)) | Pt half cell (a) Write the cell reaction ( b) Calculate emf of the cell if cell [Ni^(2+)] = 0.1 [ H^(+)] =0.05 M and E_(Ni)^(0) =- 0.257 V

Emf of a cell corresponding to the reaction:- Zn(s) +2H^(+) (aq) rarr Zn^(2+)(aq) [0.1M] +H_(2)(g) [1.0atm] is 0.49V at 25^(@)C, E_(Zn^(2+)//Zn)^(@) = - 0.76 V . The pH of solution in cathode chamber is.

A button cell used in watched funcations as follwing Zn(s)+Ag_(2)O(s)+H_(2)O(l)hArr2Ag(s)+Zn^(2+)(aq.)+2OH^(-)(aq) If half cell potentials are Zn^(2+)(aq.)+2e^(-) rarr Zn(s), E^(@) = -0.76 V Ag_(2)O(s)+H_(2)O(l)+2e^(-) rarr 2Ag(s)+2OH^(-)(aq.),, E^(@) = 0.34V The cell potential will be