Home
Class 11
CHEMISTRY
Given the folowing standerd electrode po...

Given the folowing standerd electrode potentials, the `K_(sp)` for `PbBr^(2)` is :
`PbBr_(2)(s)+2e^(-)toPb(s)+2Br^(-)(aq), E^(@)=-0.248 V`
`Pb^(2+)(aq)+2e^(-)toPb(s), E^(@)=-0.126 V`

A

`7.4xx10^(-5)`

B

`4.9xx10^(-14)`

C

`5.2xx10^(-6)`

D

`2.3xx10^(-13)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos

  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

Given the standard reduction potentials, which statement is correct? {:(Cu^(2)(aq) + 2e^(-) rightarrow Cu(s), E^(@) = 0.34V), (2H^(+)(aq) + 2e^(-) rightarrow H_(2)(g), E^(@)= 0.0V), (Cr^(3+)(aq) + 2e^(-) rightarrow Cr(s),E^(@) = -0.73V):}

Based on data given below for the electrode potential , reducing power of Fe^(2+) , Al and Br^(-) will increase in the order Br_(2)(aq)+2e^(-)rarr2Br^(-)(aq),E^@=+1.08V Al^(3+)(aq)+3e^(-)rarrAl(s),E^@=-1.66V Fe^(3+)(aq)+e^(-2)rarrFe^(+2) (aq) , E^(@) =+0.77V

Given these standard reduction potentials, what is the standard reduction potential for Co^(3+)(aq) + 3e^(-) rightarrow Co(s) ? Co^(3+)(aq) + e^(-) rightarrow Co^(2+)(aq) E^(@) = 1.82V Co^(2+)(aq) + 2e^(-) rightarrow Co(s) E^(@) = -0.28V

The standard reduction potentials at 298K for the following half cells are given : ZN^(2+)(aq)+ 2e^(-)Zn(s) , E^(@) = - 0.762V Cr^(3+)(aq)+ 3e^(-) Cr(s) , E^(@) = - 0.740V 2H^(+) (aq)+2e^(-) H_(2)(g) , E^(@)= 0.000V Fe^(3+)(aq)+ e^(-) Fe^(2+)(aq) , E^(@) = 0.770V which is the strongest reducing agent ?

The electrode potential, E^(@) , for the reduction of MnO_(4)^(-)" to "Mn^(2+) in acidic medium is +1.51V . Which of the following metal(s) will be oxidised? The reduction reactions and standard electrode potentials for Zn^(2+), Ag^(+) and Au^(+) are given as Zn_((aq))^(2+)+2e^(-)rarrZn_((s)),E^(@)=-0.762V Ag_((aq))^(+)+e^(-)hArr Ag_((x)), E^(@)=+0.80V Au_((aq))^(+)+e^(-)hArr Au_((s)), E^(@)=+1.69V

Consider the following half-cell reaction and associated standerd half-cell potentials and determine the maximum voltage thatr can be obtained by combination resulting in spontenous process : AuBr_(4)^(-)(aq)+3e^(-)toAu(s)+4BR^(-)(aq), E^(@)=-086V Eu^(3+)(aq)+e^(-)toEu^(2+)(aq), E^(@)=-043V Sn^(2+)(aq)+2e^(-)toSn(s), E^(@)=-0.14V IO^(-)(aq)+H_(2)O(l)+2e^(-)toI^(-)(aq)+2OH^(-), E^(@)=+0.49V