The free energy change due to a reaction is zero when
The standard free energy change for a reaction is -213.3 KJ mol^(-1) "at" 25^(@)C . If the enthalpy change of the reaction is -217.77 KJ "mole"^(-1) . Calculate the magnitude of entropy change for the reaction in Joule "mole"^(-1)
The free energy change for a reversible reaction at equilibrium is
The free energy change for a reversible reaction at equilibrium is
The standard free energy change of a reaction is DeltaG^(@)=-kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))
The free energy change for a reversible reaction at equilibrium is: