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calculate the value of equilibrium const...

calculate the value of equilibrium constant `(K_f)` for the reaction:
`Zn^(2+)(aq)+4OH^(-)(aq)iffZn(OH)_4^(2-)(aq)`
Given: `Zn^(2+)(aq)+2e^(-)toZn(s0,E^(@)=-0.76 V`
`Zn(OH)_4^(2-)(aq)+2e^(-)toZn(s)+4OH^(-)(aq),E^(@)=-1.36 V`
`2.303(RT)/F=0.06`

A

`10^10`

B

`2xx10^10`

C

`10^20`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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