Resistance of a 0.1 M KCl solution in a conductance cell is 300 ohm and specific conductance of "0.1 M KCl" is .133xx10^(-2)" ohm"^(-1)"cm"^(-1) . The resistance of 0.1 M NaCl solution in the same cell is 400 ohm. The equivalent conductance of the 0.1 M NaCl solution ("in ohm"^(-1)"cm"^(2)"/gmeq.") is
The resistance of 0.1N solution of formic acid is 200 ohm and cell constant is 2.0 cm^(-1) . The equivalent conductivity ( in Scm^(2) eq^(-1)) of 0.1N formic acid is :
The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0. 88cm^(-1) . The value of equivalent conductance of solution is
The resistance of a 0.01N solution of an electroyte was found to 210 ohm at 298K using a conductivity cell with a cell constant of 0.88 cm^(-1) . Calculate specific conductance and equilvalent conductance of solution.
The specific conductance of a 0.1 N KCl solution at 23^(@)C is 0.012 ohm^(-1) cm^(-1) . The resistance of cell containing the solution at the same tempreature was found to be 55 ohm . The cell constant will be