Molar conductivity of a solution of an electrolyte `AB_3` is 150`Scm^2mol^(-1)` . If it ionises as `AB_(3)toA^(3+)+3B^(-)`, its equivalent conductivity will be :
A
150 (in`Scm^2eq^(-1)`)
B
75 (in `Scm^2eq^(-1)`)
C
50 (in `Scm^2eq^(-1)`)
D
80 (in `Scm^2eq^(-1)`)
Text Solution
Verified by Experts
The correct Answer is:
C
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