A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of `2.768xx10^(-3)ohm^(-1)cm^(-1)` . If its resistance is 82.4 ohm at `25^(@)` C the cell constant is:
A
`0.2182cm^(-1)`
B
`0.2281cm^(-1)`
C
`0.2821cm^(-1)`
D
`0.2381cm^(-1)`
Text Solution
Verified by Experts
The correct Answer is:
B
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
A conductance cell was calibrated by filling it with a 0.02 M solution of potassium chloride (specific conductance = 0.2768 ohm^(-1) m^(-1) ) and measuring the resistance at 298 K which was found to be 457.3 ohm. The cell was then filled with a calcium chloride solution containing 0.555 g of CaCl_(2) per litre. The measured resistance was 1050 ohm. Calculate the molar conductivity of CaCl_(2) solution.
A conductivity cell was filled with 0.01 M solution of KCl which was known to have a specific conductivity of 0.1413 ohm^(-1) m^(-1) at 298 K. Its measured resistance at 298 K was 94.3 ohm. When the cell was filled with 0.02 M AgNO_(3) solution, its resistance was 50.3 ohm. Calculate (i) cell constant and (ii) the specific conductance of AgNO_(3) solution.
Specific conductance of 0.1 MHA is 3.75xx10^(-4)ohm^(-1)cm^(-1) . If lamda^(oo) of HA is 250 ohm^(-1)cm^2mol^(-1) , then dissociation constant K_a of HA is
Calculate the cell constant if the specific conductance of a Solution is 0.2 "ohm"^(-1)cm^(-1) and its conductance is 0.04 "ohm"^(-1) .
