Home
Class 11
CHEMISTRY
The conductance of a salt solution (AB) ...

The conductance of a salt solution (AB) measured by two parallel electodes of area `100 cm^2` separated by 10cm was found to be `0.0001Omega^(-1)` . If volume enclosed between two electrode contain 0.1 mole of salt, what is the molar conductivity `(Scm^2mol^(-1))` of salt at same concentration:

A

10

B

0.1

C

1

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos

  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

The resistance of a decinormal solution of a salt occupying a volume between two platinum electrodes which are 1.80 cm apart and 5.4 cm^(2) in area was found to be 50 omega calculate the equilvalent conductance of the solution

The resistance of 0.5M solution of an electrolyte in a cell was found to be 50 Omega . If the electrodes in the cell are 2.2 cm apart and have an area of 4.4 cm^(2) then the molar conductivity (in S m^(2) mol^(-1)) of the solution is

The resistance of decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4 cm^(2) area was found to be 32 ohm . Calculate k and wedge _(eq) .

The conductivity of 0.1 mol L^(-1) KCl solution is 1.41 xx 10^(-3) S cm^(-1) . What is its molar conductivity (in S cm^(2) mol^(-1) ) ?

1.0 N solution of a salt surrounding two platinum electrodes 2.1 cm apart and 4.2 sq cm in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductivity of the solution.

The resistance of a 0.5 M solution of an electrolyte was found to be 30 Omega enclosed between two platinum electrodes. Calculate the molar conductivity of the solution if the electrodes in the cell are 1.5 cm apart and having an area of cross section 2.0 cm^(2) ?

For an electrolyte solution of 0.05 mol L^(-1) , the conductivity has been found to be 0.0110S cm^(-1) . The molar conductivity is

The specific conductance of a salt of 0.01 M concentration is 1.061 xx 10^(-4) . Molar conductance of the same solution will be :