Given the following molar conductivity at `25^(@)` C:, HCl,426`Omega^(-1)cm^2mol^(-1)`, NaCl, `126Omega^(-1)cm^2mol^(-1)`, NaC(sodium crotonate), `83Omega^(_1)cm^2mol^(-1)`. What is the dissciation constant of crotonic acid,if the conductivity of a 0.001 M crotonic acid solution is `3.83xx10^(-5)Omega^(-1)cm^(-1)`?
A
`10^(-5)`
B
`1.11xx10^(-5)`
C
`1.11xx10^(-4)`
D
0.01
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The correct Answer is:
B
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Given the following limiting molar conductivies at 25^(@)C,, Hcl, 426Omega^(-1)cm^(2)mol^(-1),NaCl, 126Omega^(-1)cm^(2)mol^(-1),NaC (sodium crotonate) , 83Omega^(-1)cm^(2)mol^(-1) . What is the ionization constant of crotonic acid? If the conductivity of a 0.001M crotonic acid (HC) solution is 3.83xx10^(-5)Omega^(-1)cm^(-1) ?
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