Equivalent conductivity of `BaCl_2,H_2SO_4` and HCl, are `x_1,x_2"and"x_3Scm^(-1)eq^(-1)` at infinite dilution. If conductivity of saturated `BaSo_4` solution is x`Scm^(-1)`, then `K_(sp)` of `BaSO_4` is :
A
`(500x)/((x_1+x_2-x_3)^2)`
B
`(10^6x^2)/((x_1+x_2-2x_3)^3)`
C
`(2.5xx10^5x^2)/((x_1+x_2-2x_3)^2)`
D
`(0.25x^2)/((x_1+x_2-2x_3)^2)`
Text Solution
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The correct Answer is:
C
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