Following reaction can take place in both direction `A overset(k_(1))underset(k_(2))hArr B`. Graph is given for the forward reaction. And for the beackward reaction, following data is obtained:

`{:([B],Rate),(0.01M,1 xx 10^(-2)Ms^(-1)),(0.02M,2xx 10^(-2)Ms^(-1)):}`
Hence, net reaction rate of B is:

Options

A. `=k_(1) [A] - k_(2)[B]`
B. `=k_(1) - k_(2)[B]`
C. `=k_(1) [A] - k_(2)`
D. `=k_(1)-k_(2)`

Answer

B