The capacitance of a parallel -plate capacitor is `C_(0)` when the region between the plates has air. This region is now filled with a dielectric slab of dielectric constant `K`. The capacitor is connected to a cell of emf `varepsilon` and the slab is takenout

Options

A. Charge `varepsilon(C_(0)(K-1)` flows through the cell.
B. Energy `varepsilon^(2)C_(0)(K-1)` is absorbed by the cell.
C. The energy stored in the capacitor is reduced by `varepsilon^(2)C_(0)(K-1)`
D. The external agent has to do `1/2 varepsilon^(2) C_(0)(K-1)` amount of work to take the slab out.

Answer

A, B, D