`N` identical cells, each emf `E` and internal resistance `r` are joined in series. Out of `N` cells, `n` cells are wrongly connected i.e., their terminals are connected in reverse of the required for series connection `(n lt (N)/(2))`. Let `E_(0)` be the emf of resulting battery and `r_(0)` be its internal resistance. Then

Options

A. `varepsilon_(0)=(N-n)varepsilon,r_(0)=(N-n)r`
B. `varepsilon=(N-2n)varepsilon,r_(0)=(N-2n)r`
C. `varepsilon_(0)=(N-2n)varepsilon,r_(0)=Nr`
D. `varepsilon=(N-n)varepsilon,r_(0)=Nr`

Answer

C, D