An electric bulb is designed to draw P(...

An electric bulb is designed to draw `P_(0)` power at `V_(0)` voltage. If the voltage is `V`, it drawas power. Then

A

`P=(V_(0))/V P_(0)`

B

`P=V/(V_(0)) P_(0)`

C

`P=(V/(V_(0)))^(2)P_(0)`

D

`P=((V_(0))/V)^(2)P_(0)`

Text Solution

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The correct Answer is:

C, D

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