Two cells of unequal emfs, `varepsilon_(1)` and `varepsilon_(2)` and internal resistances `r_(1)` and `r_(2)` are joined as shown. `V_(A)` and `V_(B)` are the potentials at `A` and `B` respectively.

Options

A. Once cell wil continuously suply energy to the other.
B. The potential difference across botht eh cells will be equal.
C. The potential difference across one cell will be greater than its emf.
D. `V_(A)-V_(B)=((varepsilon_(1)r_(2)+varepsilon_(2)r_(1)))/((r_(1)+r_(2)))`

Answer

A, B, C, D