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A voltmeter and an ammeter are connected...

A voltmeter and an ammeter are connected in series to an ideal cell of `emf E`. The voltmeter reading is `V`, and the ammeter readings is `I`. Then
(i) `V lt E` (ii) the voltmeter resistance is `V// I`
(iii) the potential difference across the ammeter is `E - V`
(iv) Voltmeter resistance + ammeter resistance = E//I`
Correct statements are

A

`V lt varepsilon`

B

The voltmeter resistance is `V//I`

C

The potential difference acros the ammeter is `(varepsilon-V)`

D

Voltmeter resistance plus ammeter resistanc `=varepsilon//I`

Text Solution

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The correct Answer is:
A, B, C, D
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