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Three ammeters A,B, and C of resistances...

Three ammeters `A,B`, and `C` of resistances `R_A,R_b` and `R_C` respectively are joined as shown. When some potential difference is appllied across the terminals `T_1` and `T_2` their readings are `I_A,I_B and I_C` respectively Then,

A

`I_(A)=I_(B)`

B

`I_(A)R_(A)+I_(B)R_(B)=I_(C) R_(C)`

C

`(I_(A))/(I_(C))=(R_(C))/(R_(A))`

D

`(I_(B))/(I_(C))=(R_(C))/(R_(A)+R_(B))`

Text Solution

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The correct Answer is:
A, B, D
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