Halley's comet has a period of 76 years and in the year 1986, had a distance of closest approach to the sun equal to `8.9xx10^(-10)` m. What is the comet's farthest distance from the sun if the mass of sun is `2xx10^(30)`kg and `G=6.67xx10^(-11)` MKS units?

Comet Halley orbits the sun with a period of 76 years and, in 1986,had a distance of closestapproach to the Sun, its perihelion distance R_p ,of 8.9 xx 10^10m .Table 13-3 shows that this is between the orbits of Mercury and Venus. (a) What is the comet's farthest distance from the Sun, which is called its aphelion distance R_a ?

The time period of Jupiter is 11.6 years. How far is Jupiter from the Sun? Distance of the Earth from the sun is 1.5xx10^(11)m

The time period of jupiter is 11-6 year, how far is jupitor from the sun. Distance of earth from the sun is 1.5 xx 10^(11) m .

The sun's angular diameter is measured to be 1920''. The distance of the sun from the earth is 1.496xx10^(11)m. What is the diameter of the sun?

The angular diameter of the sun is 1920". If the distance of the sun from the earth is 1.5xx10^(11) m, what is the linear diameter of the sun ?

Calculate the speed of Jupiter if the mass of Jupiter is 1.9 xx 10^(27) kg . Distance from the sun is 7.8 xx 10^(11)m and the mass of the sun is 2 xx 10^(30) kg .

Mass of mars is 6.42xx10^(29) kg and mass of the sun is 1.99xx10^(30)kg . What is the total mass?

The distance of the sun from earth is 1.496xx10^(11)m. If the angular diameter of the sun is 2000'', find the diameter of the sun.

Find the velocity of escape from the sun, if its mass is 1.89xx10^(30) kg and its distance from the earth is 1.59xx10^(8) km. Take G =6.67xx10^(-11) Nm^(2) kg^(-2)

The radius of the sun is 0.75xx10^(8)m and its distance from the earth is 1.5xx10^(11)m . Find the diameter of the image of the sun formed by a lens of focal length 40 cm