A body suspended on a spring balance in a ship weighs `W_(0)` when the ship is at rest. When the ship begins to move along the equator with a speed `v`, show that the scale reading is very close to `W_(0) (1+-2omegaV//g`), where `omega` is the angular speed of the earth.

A body is suspended on a spring balance in a ship sailing along the equator with a speed v . Show that the scale reading will be very close to W_(0)(1 pm (2 omega v)/(g)) , where omega is the angular speed of the earth and W_(0) is the reading of spring balance when the ship is at rest. Explain the plus or minus sign [Hint : W_(0)=mg-momega^(2)R,W=mg-m((momega+v)^(2))/(R) when the ship is moving from west to east]

A body is suspended on a spring balance in a ship sailing along the equator with a speed v'. If omega is the angular speed of the earth and omega_(0) is the scale reading when the ship is at rest, the scale reading when the ship is sailing is

Show that the angle made by the string with the vertical in a conical pendulum is given by costheta=(g)/(Lomega^(2)) , where L is the string and omega is the angular speed.

A body is weighed with a spring balance in a train at rest, shown a weight W . When the train begins to move with a velocity upsilon around the equator from west to east and if the angular velocity of the train is omega then the weight shown by spring balance is

A body is suspended from a spring balance kept in a satellite. The reading of the balance is W_1 when the satellite goes in an orbit of radius R and is W_2 when it goes in an orbit of radius 2R.

A spring balance reads W_(1) when a ball is suspended from it. A weighing machine reads W_(2) when a tank of liquid is kept on it. When the ball is immersed in the liquid, the spring balance reads W_(3) and the weighing machine reads W_(4) . Then, which of the following are not correct?

A satellite moves estwards very near the surface of the Earth in equitorial plane with speed (v_(0)) . Another satellite moves at the same height with the same speed in the equatorial plane but westwards. If R =radius of the Earth and omega be its angular speed of the Earth about its own axis. Then find the approximate difference in the two time period as observed on the earth.

Angular speed of rotation of the earth is omega_(0). A train is running along the equator at a speed v from west to east. A very sensitive balance inside the train shows the weight of n object as W_(1). During the return journey when the train is running atsame speed from east to west the balance shows the weight of the object to be W_(2). Weight of the object when the train is at rest was shown to be W_(0) by the balance. Calculate W_(2) – W_(1).

A pendulum having a bob of mas m is hanging in a ship sailing along the equator from east to west. When the ship is stationary with respect to water the tension in tehstring is T_0 . a. Find the speed of the shp due to rotation of the earth about its axis. b. find the differecne between T_0 and th earth's attraction on the bob. c. If the ship sails at speed v. what is the tension in the string ? Angular speed of earth's rotation is omega and radius of the earth is R.